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36x^2-17x-15=0
a = 36; b = -17; c = -15;
Δ = b2-4ac
Δ = -172-4·36·(-15)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{2449}}{2*36}=\frac{17-\sqrt{2449}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{2449}}{2*36}=\frac{17+\sqrt{2449}}{72} $
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